View Full Version : Out to Dinner Mathematics
pygmalion
10-04-2003, 02:01 PM
OUT TO DINNER MATHEMATICS
This is pretty neat how it works out.
DON'T CHEAT BY SCROLLING DOWN FIRST
It takes less than a minute.......
Work this out as you read.
Don't cheat and read the bottom until you've worked through it!
This is fun!
1. First of all, pick the number of times a week that you would like to have dinner out. (try for more than once but less than 10)
2. Multiply this number by 2 (Just to be bold)
3. Add 5. (Just because)
4. Multiply it by 50 - I'll wait while you get the calculator.................
5. If you have already had your birth! day this year add 1753.... If
you haven't, add 1752..........
6.. Now subtract the four digit year that you were born.
You should have a three digit number .
The first digit of this was your original number
(How many times you want to eat out each week.)
The next two numbers are...
YOUR AGE! (Oh YES, it IS!!!!!)
This is the only year this will ever work(2003) it will ever work, so spread it around while 2003 lasts. Cool, not?
will35
10-04-2003, 02:18 PM
You can imagine how pleased I was to discover that I was really 53 years old.
pygmalion
10-04-2003, 02:28 PM
Hey Will! Are you sure you did the math right? I tried the number two and nine, for both having had your birthday this year and not having had your birthday this year for your age (you gave it in another thread!) and all four combinations worked. *shrug*
Jenn
will35
10-04-2003, 02:31 PM
I was just kidding!
SwinginBoo
10-04-2003, 07:20 PM
Hey Will! Are you sure you did the math right? I tried the number two and nine, for both having had your birthday this year and not having had your birthday this year for your age (you gave it in another thread!) and all four combinations worked. *shrug*
Jenn
I turned out to be 45. This can't be right <-- That, or I'm no mathmatician. :P
pygmalion
10-04-2003, 07:30 PM
What in the world posessed me to post a math-related item on a dance bulletin board? :shock: :? :lol:
I bet it's a math problem. Did you remember to add the five? That's where I messed up, a couple times.
Jenn :D
pygmalion
10-04-2003, 07:42 PM
I don't know when your birthday is, SwinginBoo, but here's the math for one example, using your age, which you posted in another thread.
I picked eating out two times per week, and assumed you already had your birthday.
Here's the math.
How many times per week? Two.
Multiply by two. Four.
Add five. Nine.
Multiply by fifty. Four Hundred Fifty.
Add 1753. 2203.
Subtract year of birth (1980) 223.
First digit number of times out per week = two.
Last two digits are your age = 23.
It works! For every example I've tried, which, by this point, is a lot. My computer scientist friend, who's a total math nut/whiz sent me this, so I suspect it actually works. Just goes to show that we dancers are too busy dancing to do that dumb math stuff. :lol:
Swing Kitten
10-04-2003, 09:49 PM
interesting! in that novelty sort of way.
SwinginBoo
10-04-2003, 11:44 PM
Woops, instead of adding 1753 to 2003, I subtracted them. My mistake...and I'm still no mathematician :wink:
dancersdreamland
10-05-2003, 06:50 PM
Cool...I think I've seen this before, thought...a couple years ago actually...which leads me to believe if certain numbers or items are changed this may work in other years.
Still cool, though! 8)
pygmalion
10-05-2003, 06:54 PM
Yeah. I'm pretty sure that it's one basic formula, and the basic "X" term changes a bit from year to year. I've also seen this formula many times before. And the "check" program is easy to write -- to go through all the possible combinations of birth years and ages, and check that the numbers are right -- easy stuff, if you've ever written a computer program. :D Pretty cool. :D :lol:
NeoDevin
01-03-2004, 01:14 AM
It's really simple if you think about it. You end up with your number you started with, multiplied by 100. (why the first digit is your original number) Plus 2003/2002 (1753/1752 + 5*50) minus your birth year.
PS. I am a mathematician ;)
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